0=18(x^2+x-56)

Solution for 0=18(x^2+x-56) equation:

0=18(x^2+x-56)

We move all terms to the left:

0-(18(x^2+x-56))=0

We add all the numbers together, and all the variables

-(18(x^2+x-56))=0


We calculate terms in parentheses: -(18(x^2+x-56)), so:

18(x^2+x-56)

We multiply parentheses

18x^2+18x-1008

Back to the equation:

-(18x^2+18x-1008)


We get rid of parentheses

-18x^2-18x+1008=0

a = -18; b = -18; c = +1008;
Δ = b2-4ac
Δ = -182-4·(-18)·1008
Δ = 72900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{72900}=270$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-270}{2*-18}=\frac{-252}{-36}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+270}{2*-18}=\frac{288}{-36}
=-8
$